construct a triangle ABC in which perpendicular from A to BC is 5.6 cm, angle B = 60° and angle C = 45°. (Solve step by step and write all steps)
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Hello friends...
Your answer is here.
First of all draw a line BC= 5.6cm
Now draw a 60°angle from the point B
and 45°angle from the point C.
Now, We get a point A where 60° angle and °45°angle bisect.
Now draw a line AC and line AB from the point we got. and Now You can a line that will be perpendicular to BC from the point A.
Thankyou Buddy....
Your answer is here.
First of all draw a line BC= 5.6cm
Now draw a 60°angle from the point B
and 45°angle from the point C.
Now, We get a point A where 60° angle and °45°angle bisect.
Now draw a line AC and line AB from the point we got. and Now You can a line that will be perpendicular to BC from the point A.
Thankyou Buddy....
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