Question

construct a triangle ABC of sides 6,8 and 10cm and construct similar triangle to this triangle with the sides equal to 5/4 of the corresponding sides of triangle ABC​

Answer 1

Answer:

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(1) Draw any ray making an acute angle to the vertex L.

(2) Locate 5 points (greater of 4 and 5 in 4/5) M1, M2, M3, M4, and M5 and MX so that MM1 = M1 M2 = M2 M3 = M3 M4 = M4 M5

(3) Join M5 N and draw a line parallel to M5 N through M4 (the fourth point, 4 being the smaller of 4 and 5 in 4/5) to intersect MN at N’.

(4) Draw a line through N1 parallel to the line NL to intersect ML and L’. Then ΔL’MN’ is the required triangle each of the whose sides is 4/5 of the corresponding sides of ΔLMN.

Answer 2

Answer:

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