Question

construct a triangle ABC of sides AB=4cm,BC=5cm,CA=6cm,with it's sides equal to 5/3of the corresponding sides of the triangle ABC​

Answer 1

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Answer 2

Answer:

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Explanation:

1. draw base AB=4cm

2. with A as center, with a scale of 5cm as radius draw an arc and with B as center, with a scale of 6cm as radius draw an arc.

3. let C be the point of intersection of the above 2 lines.

4. draw a ray AX making an acute angle with line AB on the opposite side if the vertex C.

5. mark 3 points A1,A2,A3 such tha A1A2=A2A3=A3A1

6. join A3B and draw a parallel line B

′

A2

7. draw a line parallel to BC to intersect AC at C

′

Thus AB C is a required triangle.