*Construct a triangle ABC such that AB = 5 cm and AC-4 cm and B = 60 degrees* .......( please give explanation and try to give answer on paper.)
Answers
Given : In Δ ABC , BC = 5am , AC + AB = 7.5cm and ∠ B = 60
∘
To construct : Δ ABC
Steps of construction :
1. Draw a ray BX and cut off a line segment BC = 5cm from it.
2. At B , construct ∠ XBY = 60
∘
.
3. With B as center and radius = 7.5cm , draw an arc at meet BY at D.
4. Join CD.
5. Draw the perpendicular bisector of CD, by marking arc of length more than half of CD from both points C and D on both sides of it.
this line will be intersecting BD at A .
6. Join AC . Then , ABC is the required triangle .
solution
1)=>>>>Answer first.
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(i) Draw a line AB = 5 cm.
(ii) B as a centre draw an angle with the help of compass ∠B = 60°. Cut the line with an arc BC = 6 4 cm.
(iii) Join AC.
(iv) Now, from A and B cut the bisector of ∠A and ∠B, which intersect each other at point D.
(v) With D as a centre draw an incircle which touches all the three sides of △ABC.
2)=>>>>>Second answer.
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We follow several steps in the construction:
1. Draw a ling segment which is sufficiently long using ruler.
2. Locate points A and B on it such that AB=5cm.
3. With A as centre and radius 4cm, draw an arc.
4. With B as centre and radius 4.3cm, draw another arc cutting the previous arc at C.
5. Join AC and BC
Then ABC is the required triangle.
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