Math, asked by satishsaha525, 4 months ago


Construct a triangle
ABC such that AB = 6.5cm AC=5cm
and the altitude Ap to BC is 4 cm.​

Answers

Answered by nisha02345
4

Answer:

Steps of construction:

(i) Draw a line segment BC=6.5cm. Draw an angle CBX=45

o

. Draw perpendicular bisector to BC show that it interest the previous perpendicular at point O.

(ii) Taken OB as radius and O as centre, draw a circle.

(iii) Intersect the perpendicular bisector PQ to make a point E at a distance of 5.5cm from the point D. Draw a perpendicular line PQ at a point E such that it intersect the circle at points A and A'.

(iv) Join AB, AC, A'B and A'C.

Thus, ABC and A'BC are the required triangles.

Attachments:
Answered by daksh12695
1

hard kyu diye bhaiya itne sare

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