Construct a triangle
ABC such that AB = 6.5cm AC=5cm
and the altitude Ap to BC is 4 cm.
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Answer:
Steps of construction:
(i) Draw a line segment BC=6.5cm. Draw an angle CBX=45
o
. Draw perpendicular bisector to BC show that it interest the previous perpendicular at point O.
(ii) Taken OB as radius and O as centre, draw a circle.
(iii) Intersect the perpendicular bisector PQ to make a point E at a distance of 5.5cm from the point D. Draw a perpendicular line PQ at a point E such that it intersect the circle at points A and A'.
(iv) Join AB, AC, A'B and A'C.
Thus, ABC and A'BC are the required triangles.
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hard kyu diye bhaiya itne sare
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