construct a triangle ABC such that BC =10 cm, Angle B =60° and Angle C = 50°.
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Answer:
Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 10cm.
Step2: Draw an angle of 60° at P and an angle of 45° at Q.
Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.
Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C
Step.5: Join AB and AC. ∴ ΔABC is the required triangle
Step-by-step explanation:
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