Construct a triangle ABC such that <B=60°, <C=45° and AB+BC+CA =10 cm.
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Step-by-step explanation:
1.draw a line segment of 10cm named by
2.at× make 1/2 of60 and 1/2of 45 to meet each other at A
3.Draw the perpendicular bisected of ca and yA which meet my at B and C
4.join BA and CA
5.ABC is the required triangle.
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