Construct a triangle ABC where AB= 5 cm , angle A = 60° and BC + AC = 2 cm
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★ Given...✒
- In Δ ABC , BC = 5am , AC + AB = 7.5cm and ∠ B = 60°
★ To construct...✒
- Δ ABC
★ Steps of construction...✒
- Draw a ray BX and cut off a line segment BC = 5cm from it.
- At B , construct ∠ XBY = 60°
- With B as center and radius = 7.5cm , draw an arc at meet BY at D.
- Join CD.
- Draw the perpendicular bisector of CD, by marking arc of length more than half of CD from both points C and D on both sides of it.
- This line will be intersecting BD at A .
- Join AC . Then , ABC is the required triangle .
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