Question

construct a triangle abc where ab=6.7 a=55 degree and ac-bc=1.2cm

Answer 1

Use this photo for answer
1. Draw AB 6.7 cm

2. Draw angle A i.e. 55°

3. Let give a line name AX

4.Draw an arc of subtracted line i.e. 1.2 cm

5. Join the line with B

6. Draw a bisector of line BD.

7. And join that line with AX and give name C

8. ABC is required Triangle.

Answer 2

The construction of ∆ABC is attached.

Given:

• A ∆ ABC.
• AB=6.7 cm, $\angle A=55^{\circ}$
• AC-BC=1.2 cm

To find:

• Construct the ∆ABC.

Solution:

Steps of construction:

1. Draw the line AB of 6.7 cm.
2. Draw $\angle XAB=55^{\circ}$ with the help of protector.
3. Draw an arc of radius 1.2 cm on ray XA.
4. Join the point L with B.
5. Draw the perpendicular bisector of LB, it intersects ray XA at point, let this point is C.
6. Join C with B.
7. Thus, construction of ∆ABC is complete.

Verification:

On measurement of sides, it is found that

AC= 8.6 cm

BC= 7.4 cm

Thus,

AC-BC=1.2 cm

Hence, verified.

Learn more:

1) construct a triangle ABC in which AC=6.2 cm

, ∠C=60° and AB-BC = 2.5 cm

https://brainly.in/question/15164115

2) construct a triangle abc in which BC = 5.6cm, AC-AB =1.6cm and angle B =45 °

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