Construct a triangle ABC where AB=7 cm , angle A = 75° and BC - AC = 3 cm.
Plz answer properly by all steps.
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Step-by-step explanation:
STEPS OF CONSTRUCTION :
Draw a ray BX and cut off a line segment BC = 7cm; from it.
At B; construct angle YBX = 75°
With B as centre and radius = 12 cm (because AB + AC = 12cm) draw an arc to meet BY at D.
Join CD.
Draw Perpendicular bisector PQ of CD intersecting BD at A.
Join AC.
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