Question

Construct a triangle ABC where AB=7 cm , angle A = 75° and BC - AC = 3 cm.

Plz answer properly by all steps.​

Answer 1

Step-by-step explanation:

STEPS OF CONSTRUCTION :

Draw a ray BX and cut off a line segment BC = 7cm; from it.

At B; construct angle YBX = 75°

With B as centre and radius = 12 cm (because AB + AC = 12cm) draw an arc to meet BY at D.

Join CD.

Draw Perpendicular bisector PQ of CD intersecting BD at A.

Join AC.