Construct a triangle ABC where
BC = 5cm , ANGLE B = 60
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sorry i can answer as im not feeling well
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1.Draw the base BC = 5 cm.
2.At the point B make an ∠XBC = 60°.
3.Cut a line segment BD equal to AB + AC = 7.5 cm from the ray BX.
4.Join DC.
5.Make an ∠DCY = ∠BDC.
6.Let CY intersect BX at A.
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