Question

Construct a triangle ABC which BC=6.5 cm, angle A = 60° and median AD=4.5 cm.

Answer 1

firstly construct a line which cm u want
construct angle at point A 60°
then,
u have now a line A and B
construct an arc BC=6.5cm at B
then,
median centre of the line AB
and name the centre point D
then construct an arc from point D to C of 4.5cm .
then join all points
I HOPE ITS HELP U

Answer 2

Step-by-step explanation:

1. Draw a-line BC=6.5 cm.

2. Draw an angle of 30° at B and at C and the rays intersect at O. Thus, we have a triangle OBC.

3. In triangle OBC, angle BOC= 120°(angle sum property of a traingle.)

4. Taking O as centre and OB as radius draw a circle which joins B and C.

5. Draw the perpendicular bisector of BC which intersect BC at D

6. Taking D as center and radius of 4.5 cm, draw an arc to intersect the circle at A.

7. Join AB, AD and AC.

8. Hence, ABC is the required triangle.

JUSTIFICATION:

The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.

Therefore, angle BAC= half of angle BOC= 60°.