Question

Construct a triangle ABC whose base BC= 8cm <B = 75° and AB+AC= 12 cm.
Write the steps of construction as well.​

Answer 1

Answer:

Draw a ray BX and cut off a line segment BC = 7cm; from it.

At B; construct angle YBX = 75°

With B as centre and radius = 12 cm (because AB + AC = 12cm) draw an arc to meet BY at D.

Join CD.

Draw Perpendicular bisector PQ of CD intersecting BD at A.

Join AC.