Question

construct a Triangle ABC whose BC = 7 cm angle a =75 degree and AC-AB=3.5 cm​

Answer 1

STEPS OF CONSTRUCTION :

•Draw a ray BX and cut off a line segment BC = 7cm; from it.

•At B; construct angle YBX = 75°

•With B as centre and radius = 12 cm (because AB + AC = 12cm) draw an arc to meet BY at D.

•Join CD.

•Draw Perpendicular bisector PQ of CD intersecting BD at A.

•Join AC..

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