Construct a triangle abc whose perimeter 12cm and whose base angles are 50 degree and 80 degree
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Hi bro
I can't draw here but give you the construction
Step-by-step explanation:
1. Draw a line segment PQ = AB + BC + CA = 12 cm.
2. Make ∠ LPQ= 45° and ∠ MQP = 60°
3. Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A.
4. Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively.
5. Join AB and AC
Answered By VanshHero
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