Question

construct a triangle ABC whose perimeter is 13 cm and whose side are in the ratio 3:4:5

Answer 1

which class question is this

Answer 2

Steps for construction of triangle is written below -

Perimeter of triangle is sum of all the three side of a triangle. In the given question, sides of triangle are in the ratio 3:4:5. Now, let the sides of triangle be 3x, 4x and 5x.

According to given formula of perimeter of triangle-

P = a+b+c

13 = 3x +4x +5x

13 = 12x

X = 13/12

X = 1.08

Now, side of triangle are -

3x = 3*1.08 = 3.24

4x = 4*1.08 = 4.32

5x = 5*1.08 = 5.4

To construct the triangle-

Make a line 5.4 cm and name it as AB.

Now take compass and open it as 4.32 cm. Keep the compass at point B and make an arc. Then again open the compass at 3.24 cm and make an arc from point A. Join the intersecting points of arc with A and B and mark it as C.

Triangle ABC is ready.