Question

Construct a triangle ABC, whose perimeter is 15cm and ∠ B = 55 and ∠ C = 60​

Answer 1

Answer:

$your \: answer$

Step-by-step explanation:

STEPS OF CONSTRUCTION:

1) Draw a line segment XY of 12 cm.

2)AT X draw angle 50o and at y draw angle 800

3)Draw a bisector of angle 50o as well as angle80o.

4)Mark the point where both the bisectors meet as A.

5)Draw the perpendicular bisector of AX and AY Meeting XY at B and C respectively.

6)Join AB and AC .

7) ABC is the required triangle.

Answer 2

Given,  

AB + BC + CA = 15 cm (perimeter)

∠B = 55° and ∠C = 60°

The steps of construction are:

Draw a line segment XY of length equal to AB + AC + BC, that is, 15 cm.

From point X, using the protractor construct ∠LXY which is equal to ∠B, that is, 55°.

From the point Y, construct ∠MYX which is equal to ∠C, that is, 60°.

Using the compass, construct the bisectors of ∠LXY and ∠MYX. Mark the point as A where these bisectors meet.

Construct the perpendicular bisector of AX and name it as PQ.

Construct the perpendicular bisector of AY and name it as RS.

Let PQ meet XY at B and RS meet XY at C.

Join the points A and B as well as A and C.

So your final triangle will be (∆ABC is the required triangle with the given measurements):