Question

Construct a triangle ABC with AB = 4 cm, BC = 7 cm and CA=6 cm. Construct the circumcircle of the
ABC.​

Answer 1

Given, to construct a circle for ΔABC with the given radius AB=6cm,BC=7cm&∠A=60

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Rough draft :- Ref. image

Main draft :- Ref. image

Construction steps :-

i) Draw a line segment AB=6cm

ii) from 'A' draw a projection of radius ∠A=60

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and mark the projection as X.

iii) Now, taking 'B' as centre draw an arc onto the projection with radius 7cm

iv) Now ΔABC is formed.

v) Now taking a radius of more than half draw the perpendicular bisectors on either sides of the triangle and join them.

vi) The point where all the perpendicular bisectors meet, from that centre draw a circle that which touches all the vertices of the triangle.

vii) Thus, circum circle for the ΔABC is formed.

viii) Now, name the centre of perpendicular bisectors as circum centre [S].

Conclusion :- Thus, the required circum circle for the ΔABC is formed.