Construct a triangle ABC , with base AB= 5cm, ∠ A = 300
and AC- BC = 2.5 cm
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Explanation:
Step of Construction:
Construct AB=5 cm
Construct ∠BAX=30
o
From AX, cut the line segment AD which is equal to AC−BC=2.5 cm
Join the point BD
Construct a perpendicular bisector of BD which meets AX at the point C
In order to obtain the required triangle ABC join BC
Justification:
We know that C lies on BD which is the perpendicular bisector
So we get
CD=BC
We know that AD=2.5 cm
It can be written as
AC−CD=2.5 cm
So we get
AC−BC=2.5 cm
Therefore, △ABC is the required triangle
hope it will help you
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