Question

construct a triangle ABC with base BC=4.2 cm, A=45° and altitude through A is 2.5 cm

Answer 1

ΔABC with base BC=4.2 cm, B=45° and altitude through A is 2.5 cm is constructed

Step-by-step explanation:

Correct Data is :

construct a triangle ABC with base BC=4.2 cm, B=45° and altitude through A is 2.5 cm

Step 1 : Draw a line segment BC = 4.2 cm using ruler

Step 2 : Draw a perpendicular at C on BC using protector /set square

Step 3 : Tale a length of 2.5 cm at from C and mark it M

Step 4 : Draw a line MN parallel to BC passing through M

Step 5 : Draw an angle of 45 deg at B using protector such that it intersect MN at  A

Step 5 : Join AC

ΔABC with base BC=4.2 cm, B=45° and altitude through A is 2.5 cm is constructed

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Answer 2

Thus, $\triangle ABC$ is the required triangle.

Step-by-step explanation:

Given,

Construct a $\triangle ABC$ where base $BC=4.2cm$,$\angle B=45$° and altitude through $A$ is $2.5cm$

Following steps:

• Draw a line segment $BC=4.2cm$ using scale.
• At point $B$,draw an angle $45$° using protector like $BX$
• At point $C$,draw a perpendicular line using protector and mark on this line like $CY=2.5cm$
• Draw a parallel line $YZ$ with $BC$ which cuts the line $BX$ is known as $A$
• Join $A$ and $C$

Now, $\triangle ABC$ is the required triangle.