Question

Construct a triangle ABC with base BC=4.5cm, angle B =60° and AB+AC=7.1cm

Answer 1

Step-by-step explanation:

1=Draw a line segment BC=5.5cm.

2=At B construct angle c, b, x=60°

3=Join c to cx.

4=constuct pq The perpendicular bisector of cx of cx to meet br at A

5=join ac

The triangle ABC is the recuared triangle.

Answer 2

Construction of ∆ABC is attached.

Given:

• ∆ABC with base BC=4.5cm,
• Angle B =60° and AB+AC=7.1cm.

To find:

• Construction of ∆ABC.

Solution:

Steps of construction:

1. Draw a line segment BC of 4.5 cm with the help of pencil and scale.
2. Draw $\angle LBC= 60^{\circ}$ ,with the help of protector or compass.We are drawing here with compass.
3. Measure an arc of radius 7.2 cm on LB.
4. Draw a line LC.
5. Draw perpendicular bisector of LC; it meets LB at a point, this is point A.
6. Join A to C.
7. Construction of ∆ABC is completely done.

Verification:

On measurement it is found that

AB=3.2 cm

AC= 3.9 cm

So,

AB+AC=7.1cm

Hence verified.

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Learn more:

1) construct a triangle ABC in which AC=6.2 cm, ∠C=60° and AB-BC = 2.5 cm

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2) construct triangle abc in which ab= 5.8 cm,bc+ca=8.4cm amd b=60%. plz send pics also

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