Construct a triangle ABC with base BC = 7cm, ∠B = 750 and AC+AB = 13 cm
Answers
Answer:
not possible
Step-by-step explanation:
because angle b is given 750 wich is not possible
Answer:
Given,
Given,to construct a ΔABC where
Given,to construct a ΔABC where BC=7cm,∠B=75 °
& AB+AC=13cm.
& AB+AC=13cm.construction steps :-
& AB+AC=13cm.construction steps :-(i) Draw a line segment BC = 7 cm as a base.
& AB+AC=13cm.construction steps :-(i) Draw a line segment BC = 7 cm as a base.(ii) Now mark ∠B=75 °
and extend it till x.
and extend it till x.(iii) Now, by taking radius 13 cm draw an arc from 'B' on the line of angle just projected.
and extend it till x.(iii) Now, by taking radius 13 cm draw an arc from 'B' on the line of angle just projected.(iv) Now mark it as 'D', & join C to D.
and extend it till x.(iii) Now, by taking radius 13 cm draw an arc from 'B' on the line of angle just projected.(iv) Now mark it as 'D', & join C to D.(v) Draw ⊥
bisectors for DC and mark them as P & Q.
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥ lar
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line.
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line.(vii) Now mark that point as 'A'.
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line.(vii) Now mark that point as 'A'.(viii) Thus, required ΔABC has been formed.
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line.(vii) Now mark that point as 'A'.(viii) Thus, required ΔABC has been formed.(ix) Now, try taking exactly 1/2 of the angle and mark an arc on B.
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line.(vii) Now mark that point as 'A'.(viii) Thus, required ΔABC has been formed.(ix) Now, try taking exactly 1/2 of the angle and mark an arc on B.Conclusion
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line.(vii) Now mark that point as 'A'.(viii) Thus, required ΔABC has been formed.(ix) Now, try taking exactly 1/2 of the angle and mark an arc on B.Conclusion ∴ The required ΔABC will BC = 7 cm,
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line.(vii) Now mark that point as 'A'.(viii) Thus, required ΔABC has been formed.(ix) Now, try taking exactly 1/2 of the angle and mark an arc on B.Conclusion ∴ The required ΔABC will BC = 7 cm,∠B=45
bisectors for DC and mark them as P & Q.(vi) Now extend a line from 'B' to the ⊥ lar bisector that cuts on C & D line.(vii) Now mark that point as 'A'.(viii) Thus, required ΔABC has been formed.(ix) Now, try taking exactly 1/2 of the angle and mark an arc on B.Conclusion ∴ The required ΔABC will BC = 7 cm,∠B=45 & AB + AC = 13 cm is constructed.