Question

Construct a triangle ABC with BC=6cm, ∠A=450

and ∠B=350
and

also write the steps of construction.

Answer 1

Step-by-step explanation:

Step-1: construct base BC = 6 cm

Step-2: using protractor draw a line at 45° from point B

Step-3: given ∠A = 100° since sum of all angles in a triangle is 180° ∴ ∠A + ∠B + ∠C = 180°

∴ 100° + 45° + ∠C = 180°

∴ ∠C = 180° - 145° = 35°

Hence construct a line at 35° from point C

Mark the intersection point as A and ∆ABC is ready

Step-4: construct a line ‘l’ below BC at any angle and also extend the segment BC

Step-5: take any distance in compass and keep the needle of compass at point B construct an arc and name the point as B1 then keep the needle at B1 and draw an arc and name the point as B2. Repeat the process till B7. By doing this we are dividing the line into 7 equal parts

Step-6: join points CB4 and construct a line parallel to CB4 from B7 on the extended line BC mark the intersection point as Q

Step-7: repeat Step5 by constructing a line at any angle to line BA

Step-8: join B4 and A and construct a line parallel to AB4 from B7 on line AB mark the intersection point as P

Join points P and Q required ∆PBQ is ready