Construct a triangle ABC with BC = 7 cm, <B =60° and AB = 6 cm. Construct another triangle whose sides are 3/5 times the corresponding sides of ΔABC
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at first you should draw a rough diagram of the triangle side
then according to the question draw line BC of 8 cm
then from B draw an angle of 60°
then extend the line up to X
then take the compass and measure 6 CM then make a cut on the line BX from B
the name the point A
benzoin A to C
then draw BY with an acute angle
locate five points B1, B2 ,B3 ,B4 and B5 on BY so that BB1 = B1B2 = B2B3 = B3B4 = B4B5
join B5C and draw line through B3 , parallel to B4C to intersect BA at Adash
(mess with the above diagram it will help you )
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