Question

construct a triangle ABC with BC is equal to 5.2 cm and angle b is equal to 30 degree and angle C is 45 degree ab + ac=9.1

Answer 1

Answer:

Step-by-step explanation:

Step 1: Draw a line segment BC 5.2 cm.

Step 2 : Draw ∠B = 45°.

Step 3 : With Center B and radius 4.8 cm, make an arc which intersects CX at D.

Step 4 : Join A to C.

Step 5 : Draw a perpendicular bisector of segment DB it intersect the line segment CD at point A.

Step 6 : Join C to A.

Answer 2

The triangle ABC is shown in figure.

Step-by-step explanation:

Given that  

$\angle B = 30^{o}, \, \angle C = 45^{o}$

And sides BC = 5.2 cm, AB + AC = 9.1 cm

We know that the sum all interior angle of triangle is .

$\angle A + \angle B +\angle C = 180^{o} \\\\\angle A + 30^{o}+45^{o} =180^{o}\\\\\angle A = 105^{o}$

Procedure  to construct triangle ABC

Consider line BC = 5.2 cm as the base line.

At vertex B and C draw angle respectively.

Extend the vertex B and C until it does not cut at point A  

Measure the angle$\angle A =105^{o}$

The triangle ABC is shown in figure.

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