Question

construct a triangle ABC with perimeter 11 cm and base angle 90° and60°.??

Answer 1

Step 1:
Draw a line segment AB of 11 cm.

(As XY + YZ + ZX = 11 cm)
Step 2:

Construct an angle, ∠PAB, of 30� at point A and an angle, ∠QBA, of 90degree at point B.

Step 3:
Bisect ∠PAB and ∠QBA. Let these bisectors intersect each other at point X.

Step 4:
Draw perpendicular bisector ST of AX and UV of BX.

Step 5:

Let ST intersect AB at Y and UV intersect AB at Z.

Step 6:
Join XY, XZ.

Thus, ΔXYZ is the required triangle.(hope you like it add on brainlist)

Answer 2

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