Question

Construct a triangle ABC with side BC= 7 cm angle B = 90°, AB = 6cm. Then construct another

triangle whose sides are 2/3 times the corresponding sides of the triangle ABC​

Answer 1

Step-by-step explanation:

The ΔA

′

BC

′

whose sides are

4

3

of the corresponding sides of ΔABC can be drawn as follows:

Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60

∘

Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

Step 3: Locate 4 points, B

1

,B

2

,B

3

,B

4

on line segment BX.

Step 4: Join B

4

C and draw a line through B

3

, parallel to B

4

C intersecting BC at C

′

.

Step 5: Draw a line through C

′

parallel to AC intersecting AB at A

′

.

The triangle A

′

BC

′

is the required triangle.

Answer 2

Step-by-step explanation:

step 1: draw a ∆ABC with side BC=6cm ,AB=5cm,angle ABC =60.

step 2:draw a ray BX making an acute angle with BC on the opposite side of vextex A.

step 3: locate 4, points B1 , B2 , B3 ,B4 and draw a line through B3, parallel to B4.C intersecting BC at C.

step 5: Draw a line through C, parallel to AC intersecting AB at A.