Math, asked by siddhantkeshari98, 1 year ago

Construct a triangle ABC with side BC = 7 cm,  B = 45,  A = 105. Then construct another triangle whose sides are 4 3 times the corresponding sides of the  ABC

Answers

Answered by thesmartlerner
1

Answer:


Constructing triangle ABC in which AB = 5.8 cm , BC + CA = 8.4 cm and ∠B = 45°. ... Step 5 : Draw a perpendicular bisector of segment DA it intersect the line ... Construct a triangle ABC in which BC = 3.4 cm , AB - AC = 1.5 cm and ∠B = 45 0 .

Answered by Anonymous
20

Answer:-

To find:-

  • ∠C = ?

Given:-

  • ∠B = 45°, ∠A = 105°

We know that:-

  • Sum of all interior angles in a triangle is 180°.

∠A + ∠B + ∠C = 180°

105° + 45° + ∠C = 180°

∠C = 180° − 150°

∠C = 30°

STEPS OF CONSTRUCTION:-.

→ Draw a ΔABC with side measures of base BC = 7 cm, ∠B = 45°, and ∠C = 30°.

→ Draw a ray BX which makes an acute angle with BC on the opposite side of vertex A.

→ Now, locate 4 points such as B¹, B², B³, B⁴, on the ray BX.

→ Join the points B³C.

→ Draw a line through B⁴ parallel to B³C which intersects the extended line BC at C'.

→ Therefore, ΔA'BC' is the required triangle.

Note:- Look into the attechment for diagram.

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