Construct a triangle ABC with side BC = 7 cm, B = 45, A = 105. Then construct another triangle whose sides are 4 3 times the corresponding sides of the ABC
Answers
Answer:
Constructing triangle ABC in which AB = 5.8 cm , BC + CA = 8.4 cm and ∠B = 45°. ... Step 5 : Draw a perpendicular bisector of segment DA it intersect the line ... Construct a triangle ABC in which BC = 3.4 cm , AB - AC = 1.5 cm and ∠B = 45 0 .
Answer:-
To find:-
- ∠C = ?
Given:-
- ∠B = 45°, ∠A = 105°
We know that:-
- Sum of all interior angles in a triangle is 180°.
∠A + ∠B + ∠C = 180°
105° + 45° + ∠C = 180°
∠C = 180° − 150°
∠C = 30°
★ STEPS OF CONSTRUCTION:-.
→ Draw a ΔABC with side measures of base BC = 7 cm, ∠B = 45°, and ∠C = 30°.
→ Draw a ray BX which makes an acute angle with BC on the opposite side of vertex A.
→ Now, locate 4 points such as B¹, B², B³, B⁴, on the ray BX.
→ Join the points B³C.
→ Draw a line through B⁴ parallel to B³C which intersects the extended line BC at C'.
→ Therefore, ΔA'BC' is the required triangle.
★ Note:- Look into the attechment for diagram.