construct a triangle abc with side bc is equal to 5 cm angle b is equals to 40 degree and difference of other two sides is 3 cm
pls draw with pen paper
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Answer:
1. Draw a line segment BC=5 cm
2. Draw BX such that ∠CBX=40
∘
3. Draw BY⊥BX.
4. Draw the perpendicular bisector of BC intersecting BY at O and BC at M.
5. With O as centre and OB as radius, draw the circle.
6. The major arc BKC of the circle, contains the vertical angle 40
∘
.
7. With M as centre draw an arc of radius 6 cm meeting the circle at A and A
′
.
8. Completer △ABC on A
′
BC which is the required triangle.
9. Produce CB to CZ.
10. Draw AE⊥CZ.
11. Length of the altitude =5.1 cm.
Step-by-step explanation:
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