Question

construct a triangle ABC with the sides 4.5cm,5.5cm and 6.5cm and then construct another triangle whose sides are 4/3 of the corresponding sides of the first triangle​

Answer 1

Answer:

Step-by-step explanation:

Please find below the solution to the asked query:

We follow these steps to construct angle ABC   .

Step 1 :  Draw a line BC = 6.5 cm  .

Step 2 :  Now take any radius ( Less than half of BC ) and take center  " C "  draw an arc that intersect our line BC at  " P " , With same radius and center is " P "  draw another arc that intersect our previous  arc at "  Q " .

Step 3 :    Join CQ and extend it to D

Step 4 :  Take radius = 4,5 cm and center "  B "  we draw an arcs that intersect our line BD at "  A "  Now we join AB , and get triangle ABC .

Now We construct another triangle with scale factor 45 , As :

              

Step 5 : Draw a line CX  As  ∠ BCX is any acute angle and draw five equal radius arc on line CX that intersect at X1 . X2 , X3 , X4 and X5AS :

  CX1  = X1 X2 = X2 X3 = X3X4 = X4X5 

Step 6 : Join X5 to B and than draw a line from X4  as parallel to X5B that intersect our line BC at B' .

Step 7 : Draw line from B' as parallel to AB that intersect line AC at A' 

We get triangle A'B'C whose sides are 45 of corresponding sides of triangle ABC .

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