construct a triangle abc with the sides bc=7cm,angle b=45 degree and angle c=75 degree and then construct another triangle whose sides are 4/5 of the corresponding sides of first triangle.
can anyone solve this please.
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Answer:
let say another triangle was XYZ...
BC= 7 cm , YZ = 7×4/5
And for angel B , tan B = AC/BC
Therefore tan 45°= AC/7 SO, 1 = AC/7, Therefore AC =7 cm....
So, XZ = 7×4/5
Step-by-step explanation:
About next side , I forgot formula .... I hope it will be helpful to you....
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