construct a triangle DEF in which angle DEF = 90 degree and DE = EF= 4 cm.
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Steps of construction:
1.Draw a line segment XY
2.Locate Q,R on XY such that QR=3cm
3.Construct a line segment SR, sufficiently large, such that ∠R=90∘
4.With Q as centre and radius 4cm draw an arc, cutting RS at P; join PR.
Then, PQR is the required triangle.
Step-by-step explanation:
Thank you and please make me brainlist
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