Question

Construct a triangle DEF in which DE = 3 cm
m, EF=2.9 em and DF=5.4 cm.​

Answer 1

Answer:

The diagram is given up.

The steps of construction are -

1. Draw a line segment DF = 3cm

2. Draw a semi circle of any radius. Cut an arc on the semi circle using the same radius.

3. Again , using the same radius cut an arc from the previous arc.

4. Now from each arc on the semi circle, make two arcs cutting each other.

5. Now, from point D, using radius of 5 cm, straight from point D and name it point E.

6. Join DE and EF.

7. Hence, EDF is the required triangle.

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saisid1984

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73 people helped

Step-by-step explanation:

by the way according to Pythagoras theorem this sum is wrong

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Answer 2

Answer:

The diagram is given up.

The steps of construction are -

1. Draw a line segment DF = 3cm

2. Draw a semi circle of any radius. Cut an arc on the semi circle using the same radius.

3. Again , using the same radius cut an arc from the previous arc.

4. Now from each arc on the semi circle, make two arcs cutting each other.

5. Now, from point D, using radius of 5 cm, straight from point D and name it point E.

6. Join DE and EF.

7. Hence, EDF is the required triangle.

Hope you like it