Construct a triangle DEF such that DE=5cm DF=3cm. and angle EDF=90.with steps of construction.
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Answered by
150
The diagram is given up.
The steps of construction are -
1. Draw a line segment DF = 3cm
2. Draw a semi circle of any radius. Cut an arc on the semi circle using the same radius.
3. Again , using the same radius cut an arc from the previous arc.
4. Now from each arc on the semi circle, make two arcs cutting each other.
5. Now, from point D, using radius of 5 cm, straight from point D and name it point E.
6. Join DE and EF.
7. Hence, EDF is the required triangle.
Hope you like it
The steps of construction are -
1. Draw a line segment DF = 3cm
2. Draw a semi circle of any radius. Cut an arc on the semi circle using the same radius.
3. Again , using the same radius cut an arc from the previous arc.
4. Now from each arc on the semi circle, make two arcs cutting each other.
5. Now, from point D, using radius of 5 cm, straight from point D and name it point E.
6. Join DE and EF.
7. Hence, EDF is the required triangle.
Hope you like it
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Answered by
12
Step-by-step explanation:
by the way according to Pythagoras theorem this sum is wrong
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