Construct a triangle each of whose altitudes measure 5.4 cm. Measure each of its sides.
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1)Construct a line XY
2)Mark a point P on the line XY From the point P,
- construct PQ perpendicular to XY From the point P, mark the point PA = 5.4 cm, which cuts the line PQ at the point A Draw ∠PAB = 30o and ∠PAC = 30o which meets the line XY at the points B and C Therefore, ABC is the required equilateral triangle.
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