construct a triangle ECD with EC = ED = 6.8cm,CD = 5.6 cm. what is special name is given to such triangle
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Answer:
The required triangle is drawn in the attachment.
STEPS:
- Draw a line segment CD = 5.6cm.
- Taking C as a point, draw an arc of 6.8cm.
- Similarly, Taking D as a point, draw an arc of 6.8 cm which intersects the arc draw by point C.
- Both arcs interest at a particular point E.
- Join CE and DE.
- DE = CE = 6.8cm.
Hence, ∆ECD is the required triangle.
The triangle is isosceles triangle because 2 sides of a triangle are equal and other one side is different.
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