Question

Construct a triangle having perimeter 6,4 cm and it's base angle are 60° and 45°.​

Answer 1

Step-by-step explanation:

1. draw a line s segment of 6.4 cm name it as PQ.

2. construct a angle of 60° using protractor.

3. now draw a angle of 45° at point Q

4. now we will draw the angle bisector of angle XPQ by first making point S and T.

• taking S and T as a center draw an arc. then joint the point of their interaction at point P.

5. now we will draw an angle of bisector of angle YQP by first making M and N .

• taking M and N as a center draw an arc. then joint the point of their interaction at point Q.

6. now draw perpendicular bisector of AP and AQ which intersects the line segment PQ at point B and C respectively.

7. now join AB and AC to get the required ∆

# ∆ ABC is the required triangle.

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