Question

Construct a triangle in which angle b =120° bc =3cm& kb+kc=4.7cm give only justification​.No wrong answers, or will be reported

Answer 1

Answer:

please see the picture dear.....

Answer 2

Answer:

$\Huge{\boxed{\mathbb{\fcolorbox{blue}{purple}{HELLO!!}}}}$

$\huge\bold\pink\bigstar{Answer}$

The steps of construction to be followed:

Step 1: Draw a line segment BC = 8cm and make an angle of

at point B i.e.,

XBC

Step 2: Now, cut the line segment BD = 3.5 cm on ray BX. i.e.

.

Step 3: Join CD and draw a perpendicular bisector of CD i.e., PQ.

XCD 45

Step 4: Let the perpendicular bisector of CD intersects BX at point A. Then,

atep 3

Step 5: Join AC, to get the required triangle