Construct a triangle in which angle B=45 degree angle C= 60 degree and the perpendicular from the vertex A to the base BC is 5.2 cm
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of line perpendicular DY as C
The resulting triangle ABC angle B=45
angel C=60 and the Perpendicular from the vertex A to the base BC is 4.5 cm
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Construct a line XY Consider a point P on the line XY and draw PQ perpendicular to the line XY Along with PQ set off PA = 4.5 cm From the point A, construct LM parallel to XY Draw ∠LAB = 45o and ∠MAC = 60o which meets the line XY at the points B and C Therefore, △ ABC is the required triangle.
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