Question

construct a triangle in which angle B =60 , BC = 6.7 cm and AB +AC =10 cm

Answer 1

steps of construction
draw a line BC of 6.7 cm
now draw an angle of 60° with compass
now extend the angle to a point D such that BD=10 cm
now join DC
draw a perpendicular bisector of DC and name the point as A where the perpendicular bisector of BD intersects at line segment BD
join AC
so ABC is the required triangle