Question

construct a triangle in which base is 8cm and vertex angle is 60 degrees​

Answer 1

Answer:

Draw a line segment AB = 6 cm.

2. Make an angle PAB = 60˚

3. Draw the perpendicular bisectors LM of AB.

4. Draw TA ⊥ AP at A.



5. Let LM and TA intersect at O.

6. Draw the circle with centre O and radius OA. Then any angle in the major segment, ∠PAB = 60˚ (Angle in alternate segment).

7. Let LM intersect AB at N, then N is the mid-point of AB. Taking N as centre and 4 cm radius, draw arcs intersecting the circle C, C’.

8.Join CA, CB and C’A and C’B. Then the required  triangle is ABC or ABC’.

Answer 2

Answer:

hope it helps

Explanation: