Question

construct a triangle in which BC=7.5,angle B=60,altitude AD=3 cm,construct a circle to touch BC at its midpoint and to pass through A​

Answer 1

Answer:

Draw a straight line.

Name the left hand side as b and with the help of a campus cut a length of 7.5 cm measured from b. Name the distance as bc.

Now, with the help of campus construct an angle of 60 degree at b.

As per the given condition, the altitude of the triangle should be 3 cm.

The area of the triangle is \frac{3\times7.5}{2}

2

3×7.5

.

Let, the perpendicular should be drawn at a distance of x cm from the point b.

Hence, \begin{lgathered}tan 60 = \frac{3}{x} \\x = \sqrt{3}\end{lgathered}

tan60=

x

3

x=

3

.

At a distance of \sqrt{3}

3

the perpendicular should be drawn, so that the altitude will be 3 cm.

The midpoint of bc is 3.75 cm from b.

Name the midpoint as p.

Join p and a.

Take the midpoint of ap as q. Construct a circle centered at q with a radius of aq.

Answer 2

Answer:

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