construct a triangle in which BC equal to 3.5 CM Angle B equal to 45 degrees AB + AC equal to 6.5 CM
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1.draw a line segment BC with length 3.5cm
2.with B as center draw a line BX making angle 45°
3.then cut an arc of length 6.5cm and mark the point as Y
4. From Y as centre draw an arc with radius greater than the centre of line BY and from B as centre do the same ( drawing perpendicular line)
5.mark the perpendicularly intersecting point on BY as A
6.joint the points A and C
Thus required triangle ABC is obtained
2.with B as center draw a line BX making angle 45°
3.then cut an arc of length 6.5cm and mark the point as Y
4. From Y as centre draw an arc with radius greater than the centre of line BY and from B as centre do the same ( drawing perpendicular line)
5.mark the perpendicularly intersecting point on BY as A
6.joint the points A and C
Thus required triangle ABC is obtained
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