Question

.construct a triangle in which its base is 8 cm and vertex angle is 60°.​

Answer 1

Draw a line segment AB = 6 cm.

2. Make an angle PAB = 60°

3. Draw the perpendicular bisectors LM of AB.

4. Draw TA I AP at A.

5. Let LM and TA intersect at O.

6. Draw the circle with centre O and radius OA. Then any angle in the major segment, ZPAB= 60° (Angle in alternate segment).

7. Let LM intersect AB at N, then N is the mid-point of AB. Taking N as centre and 4 cm radius, draw arcs intersecting the circle C, C'.

8.Join CA, CB and C'A and C'B. Then the required triangle is ABC or ABC'.