Question

Construct a Triangle in which $\overline {BC}$ = 3.4 cm, $\overline {AB} - \overline {AC}$ = 1.5 cm & ∠B = 45°
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[Steps Involved ; Attachment of the Constructed Triangle - Mandatory]
$\mathfrak {\red {Topic} - Class\: 9 - Construction\: of\: Triangles}$
$\mathfrak {Spams\: aren't\: Entertained}$
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#HappyLearning!

Answer 1

1. Draw a line segment BC = 3.4cm

2. Construct 45° at B and extend line BP

3. Take 1.5cm in compass and cut an arc at

BP. Join CX. Take the bisector of CX.

4. It intersects with a point on BP. That point is A.

5. Join AC.

Hope it's helpful for you....

Answer 2

$here \: is \: required \: answer$

• Draw a line segment BC of 3.5cm.

• At B, draw an angle XBC of 45°

• With center B and radius 1.5cm, draw an arc which intersects BX at D.

• Join DC

• Draw the perpendicular bisector of DC which intersects BD produced at A.

• Join AC

Therefore Δ ABC is the required triangle