Construct a triangle LMN such that LM = LN = 4.8 cm and MN = 5.3 cm.
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1. Draw LN=7cm.
2. With L as centre and radius =6.4cm, draw an arc at M.
3. With N as centre and radius =5.5cm, draw an arc at M.
4. Join LM, MN.
5. Hence Δ LMN is the required triangle.
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