Math, asked by sharath39, 1 year ago

Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose
sides are 2/3
of the corresponding sides of the first triangle.​

Answers

Answered by 9912559168sgmailcom
2

Step-by-step explanation:

draw 5 centimetres line draw an arc of 6 cm and 4 cm line and join the arces

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Answered by Anonymous
23

Answer:-

STEPS OF CONSTRUCTION:-

→ Draw a line segment AB where AB = 4 cm.

→ Take the point A as centre and draw an arc of radius 5 cm.

→ Similarly, take the point B as its centre, and draw an arc of radius 6 cm .

→ The arcs drawn will intersect each other at point C.

→ Draw a ray AX which makes an acute angle with the line segment AB on the opposite side of vertex C.

→ Now, locate 3 points such as A1, A2, A3 on line AX such that it becomes AA¹= A¹A² = A²A³.

→ Join the point BA³ and draw a line through A² which is parallel to the line BA³ that intersect AB at point B’.

→ Therefore, ΔAB'C' is the required triangle.

Note:- Look into the attechment for the diagram.

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