Question

Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides
are 2/3 of the corresponding sides of the first triangle.​

Answer 1

Step-by-step explanation:

First of all we construct a base triangle by taking AB =4cm BC=6cm and AC=5cm

then shown in the pic..

Answer 2

Answer:

1) let A(∆ABC) : A(∆PQR) =2:3

2) suppose AB=4cm,BC=5cm,AC=6cm

3)∆ABC ~ ∆PQR

therefore,A(∆ABC):(∆PQR)=AB:PQ=BC:QR=AC:PR

2:3=4:PQ , 2:3=5:QR , 2:3=6:PR

PQ=6cm

QR=7.5cm

PR=9cm