Question

Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides are (2/3) of the corresponding sides of it.

Answer 1

Answer:

do same as this:-

Question:-

ΔABC is an isosceles triangle in which ∠C= 90° . If AC = 6 cm, then AB=

A. 6√2 cm

B. 6 cm

C. 2√6 cm

D. 4√2cm

Answer:-

In triangle ABC

Let tge altitude be AD on BC

AC=25cm

AB=25cm

BC=14cm

Therefore DC= 1/2*BC

=1/2*14

=7

By Pythagoras theorem,

AD^2+CD^2=AC^2

AD^2+7^2=25^2

AD^2+49=625

AD^2=625-49

AD^2=576

AD=24

Therefore altitude from A on BC is 24 cm

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Answer 2

Answer:

$hello$

1) DrawBC=4cm

2) Cut arc of 5 cm from B and arc of 6 cm from C. Mark point of intersection as A.

3) Draw BD making an acute angle with BC. Mark 5 equal arcs on BD.

4) Join B

5to C, draw a line B

3C ′ parallel to B 5 C.

5) Draw a line C′ A ' parallel to CA.

A' BC′ ia the required triangle.