construct a triangle of sides 4 cm, 5 cm, and 6 cm and then a triangle similar to it whose sides are 3/4 of the corresponding sides of the first triangle . (can you show on by constructing on sheet)
Answers
Step-by-step explanation:
Steps of Construction:
Step I: AB = 6 cm is drawn.
Step II: With A as a centre and radius equal to 4cm, an arc is draw.
Step III: Again, with B as a centre and radius equal to 5 cm an arc is drawn on same side of AB intersecting previous arc at C.
Step IV: AC and BC are joined to form ΔABC.
Step V: A ray AX is drawn making an acute angle with AB below it.
Step VI: 5 equal points (sum of the ratio = 2 + 3 =5) is marked on AX as A1 A2....A5
Step VII: A5B is joined. A2B' is drawn parallel to A5B and B'C' is drawn parallel to BC.
ΔAB'C' is the required triangle
Justification:
∠A(Common)
∠C = ∠C' and ∠B = ∠ B' (corresponding angles)
Thus ΔAB'C' ~ ΔABC by AAA similarity condition
From the figure,
AB'/AB = AA2/AA5 = 2/3
AB' =2/3 AB
AC' = 2/3 AC
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MY PLEASURE
Step-by-step explanation:
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